Question

Calculati: a)1^2020-2020^0+3^2-2^3 b) 2^12 :2^10+5^2-3^2+2018^0 c)2019^0+1^2019 +2018^1+0^2018-2017^1 Va rog dau coroana

Answer 1

Răspuns:

Explicație pas cu pas:

a)1^2020-2020^0+3^2-2^3

= 1 - 1 + 9 - 8 = 1

b) 2^12 :2^10+5^2-3^2+2018^0

= 2^2 + 25 - 9 + 1  = 4 + 25 - 9 + 1 = 21

c)2019^0+1^2019 +2018^1+0^2018-2017^1

= 1 + 1 + 2018 + 0 - 2017

= 3

Answer 2

Răspuns:

a)

${1}^{2020} - {2020}^{0} + {3}^{2} - {2}^{3} = 1 - 1 + 9 - 8 = \boxed{1}$

b)

${2}^{12}\div {2}^{10} + {5}^{2} - {3}^{2} + {2018}^{0} = \\ \\ {2}^{12 - 10} + 25 - 9 + 1 = \\ \\ {2}^{2} + 17 = \\ \\ 4 + 17 = \\ \\ \boxed{ 21}$

c)

${2019}^{0} + {1}^{2019} + {2018}^{1} + {0}^{2018} - {2017}^{1} = \\ \\ 1 + 1 + 2018 + 0 - 2017 = \\ \\ 2020 - 2017 = \\ \\ \boxed{3}$