Question

Calculaţi:
a) √3² +4² +12² - (√13)² ;
b) √12:√3+√32:√2-√3² +4²;​

Answer 1

$\sqrt{3^2+4^2+12^2}-(\sqrt{13})^2=\sqrt{9+16+144}-13=\sqrt{169}-13=13-13=0\\\sqrt{12}:\sqrt3+\sqrt{32} :\sqrt2-\sqrt{3^2+4^2}=\sqrt4+\sqrt{16}-\sqrt{25}=2+4-5=1$

Answer 2

a) 3+ 16 + 144 - 13= 150
b) 2 + 4 - 3 + 16= 19