Question

Calculati aria triunghiului ABC daca a). AB=4√2 cm AC=6√2 cm m(a)90° b) AC=12√6 cm, AB=BC m(b)90° c). AB=6,4 cm AC=15cm m(a)150°

Answer 1

     
$a) \\ \Delta ABC = \text{triunghi dreptunghic.} \\ =\ \textgreater \ A = \frac{AB*AC}{2} = \frac{4 \sqrt{2} *6 \sqrt{2}}{2}= \frac{24*2}{2} =24\;cm^2 \\ \\ b) \\ \Delta ABC = \text{triunghi dreptunghic isoscel cu ipotenuza AC.} \\ =\ \textgreater \ A= \frac{AC^2}{4}= \frac{(12 \sqrt{6} )^2}{4} = \frac{144*6 }{4}=36*6 = 216\;cm^2 \\ \\ c) \\ \Delta ABC = \text{triunghi obtuzunghic, in care avem AB, AC si unghiul A.} \\ =\ \textgreater \ A= \frac{AB*AC*sin(\ \textless \ A)}{2}= \frac{6,4*15*sin150^o}{2}=\frac{6,4*15* \frac{1}{2} }{2}=\frac{6,4*15}{4}=24\;cm^2$