Question

Calculati cantitatea de caldura care se degaja la arderea unui mol de acetilena(C2H2)in conditii standard stiind ca din reacti rezulta dioxid de carbon si apa.
C+O2=CO2 delta h(1)= -393,5 kJ/mol
H2+1/2O2=H2O delta h(2)= -285,8 kJ/mol
C+1/2 H2=1/2 C2H2 delta h(3)= 113,4 kJ/mol

Answer 1

C2H2(g) + 5/2O2(g) => 2CO2(g) + H2O(l) + Q

ΔH = 2ΔHr1+ΔHr2-2ΔHr3 = 2(-393,5)+(-285,8)+(-2)*(113,4) = -1299,6 KJ/mol