Question

Calculați folosind proprietatea a la m : a la n egal cu a la m minus n

Answer 1

$a^\big{n} = a^\big{m-n} \Rightarrow a^\big{n} = a^\big{m}\cdot a^\big{-n} \Rightarrow a^\big{m} = \dfrac{a^\big{n}}{a^\big{-n}} \Rightarrow a^\big{m} = a^\big{n-(-n)} \Rightarrow \\ \\ \Rightarrow \boxed{a^\big{m} = a^\big{2n}}$