Question

n = 4^{0} + 4^{1} + 4^{2} + ... + 4^{117}
n = ?

"^" inseamna "la puterea"

Answer 1

$n=1+4+4^2+...+4^{117}$
$=\frac{4^{118}-1}{3}$
$\frac{4^{118}-1}{3}:10$
$=\frac{4^{118}-1}{3}\cdot\frac{1}{10}$
$=\frac{4^{118}-1}{30}$