Question

calculati masa de aluminiu necesara pentru a interactiona cu 30 mol de acidul sulfuric. ce cantitate de sare se obtine la urma reactiei?

Answer 1

2Al + 3H2SO4 ---> Al2(SO4)3 + 3H2
2mol Al.......3mol H2SO4...1 mol sare Al2(SO4)3
x=20mol...30mol H2SO4..y=10 mol sare
MAl=27g/mol
n=m/M==>m=n*M=20*27=540g Al
MAl2(SO4)3= 2AAl+3(AS+4AO)=2*27+3(32+4*16)=342g/mol
n=m/M==>m=10*342=3420g Al2(SO4)3 sare

Answer 2

2 Al + 3 H2SO4 = Al2(SO4)3 + 3 H2
3 mol acid.........2*27 g aluminiu..........342 g sulfat
30 moli acid..............x g aluminiu.........y g sulfat
x = 540 g aluminiu
y = 3420 g sulfat = 3.42 kg sulfat de aluminiu