Question

calculati media asimetrica si media geometrica a perechilor de numere a si b
a) 152 20 5 radical 3 2+radical2 4radical2 8radical3
B)45 50 4radical3 2-radical2 5radical6 9radical2
Va rog dau coroana

Answer 1

Explicație pas cu pas:

$m_{a} = \dfrac{152 + 45}{2} = \dfrac{197}{2} = 98 \dfrac{1}{2}$

$m_{g} = \sqrt{152 \cdot 45} = \sqrt{ {6}^{2} \cdot 190} = 6 \sqrt{190}$

$m_{a} = \dfrac{20 + 50}{2} = \dfrac{70}{2} = 35$

$m_{g} = \sqrt{20 \cdot 50} = \sqrt{ {10}^{3} } = 10 \sqrt{10}$

$m_{a} = \dfrac{5 \sqrt{3} + 4 \sqrt{3} }{2} = \dfrac{9 \sqrt{3} }{2}$

$m_{g} = \sqrt{5 \sqrt{3} \cdot 4 \sqrt{3} } = \sqrt{20 \cdot 3} = 2 \sqrt{15}$

$m_{a} = \dfrac{2 + \sqrt{2} + 2 - \sqrt{2} }{2} = \dfrac{4}{2} = 2$

$m_{g} = \sqrt{(2 + \sqrt{2})(2 - \sqrt{2}) } = \sqrt{4 - 2} = \bf \sqrt{2}$