Question

calculati suma dintre dublul lui a si triplul lui b stiind ca . a=33-3x[3+3x(3-3:3)]+3x0,b=[165-(78:2-3x6-18:3)x8]:5 dau corona

Answer 1

a=33-3x[3+3x(3-3:3)]+3x0=
=33-3x[3+3x(3-1)]+0=
=33-3x(3+6)=
=33-3x9=
=33-27=
=6

b=[165-(78:2-3x6-18:3)x8]:5 =
=[165-(39-18-6)x8]:5 =
=(165-15x8):5 =
=(165-120):5 =
=45:5 =
=9

6x2=12
9x3=27
12-27=-15