Question

Calculați
Va rog frumos!!!!!!!!

Answer 1

Ai răspuns pe foaie.

Answer 2

Răspuns

Explicație pas cu pas:

a.    (2-3x)\(x²-x)+2\(x-1)+5\3x=(2-3x)x(x-1)+2\x-1+5\3x=3(2-3x)+6x+5(x-1)\3x(x-1)=(6-9x+6x+5x-5)\3x(x-1)=(2x+1)\3x(x-1)

b.  ( x-1)\(x-2)-(x+3)\(x+2)+2\(x²-4)=(x+2)(x-1)-(x-2)(x+3)+2\(x+2)(x-2)=(x²+2x-x-2(x²-2x+3x-6)+2\x²-4=6\x²-4     - am redus termenii asemenea

c.    (2x-5)\(3x-1)-(2x+3)\(3x+1)+(2x+8)\9x²-1=(3x+1)(2x-5)-(3x-1)(2x+3)+2x+8 toata egalitatea\9x²-1=6x+2x-15x-5-(6x²-2x+9x-3)+2x+8 totul supra 9x²-1=(6x²-13x-5-6x²+2x-9x+3+2x+8)totul \9x²-1=(18+6)\9x²-1=6(3x+1)\(3x+1)(3x-1)=6\(3x-1)

d.   (3x+1)\(2x²-6x)-(x+2)(3x-9)+(2x-1)\6x=(3x+1)\2x(x-3)-2x(x+2)\3(x-3)+(2x-1)\6x=3(3x+1)-2x(x+2)+(x-3)(2x-1) totul \6x(x-3)=(9x+3-2x²-4x+2x²-6x-x+3) totul \6x(x-3)=(-2x+6)\6x(x-3)=2(x-3)\6x(x-3)=-1\3