Question

Calculeaza:
a)(2+√3)²
b)(1+√2)²
c)(√5+2)²
d)(2√3+1)²
e)(√3-2)²
f)(2-√2)²
g)(3-√3)²
h)(3√2-1)²
i)(1+√3)(1-√3)

Answer 1

a)(2+√3)²=4+4√3+3=7+√3
b)(1+√2)²=1+2√2+2=3+2√2
c)(√5+2)²=5+4√5+4=9+4√5
d)(2√3+1)²=12+4√3+1=13+4√3
e)(√3-2)²=3-4√3+4=7+4√3
f)(2-√2)²=4-4√2+2=6+4√2
g)(3-√3)²=9-6√3+3=12-6√3
h)(3√2-1)²=18-6√2+1=19-6√2
i)(1+√3)(1-√3)=1-3=-2

Answer 2

[tex](2+ \sqrt{3})^2=4+3+4 \sqrt{3} =7+4 \sqrt{3} \\ (1+ \sqrt{2})^2= 1+2+2 \sqrt{2}=3+2 \sqrt{2} \\ \sqrt{5}+2)^2=5+4+4 \sqrt{5}=9+4 \sqrt{5} \\ (2 \sqrt{3}+1)^2=12+1+4 \sqrt{3}=13+4 \sqrt{3} \\ ( \sqrt{3}-2)^2=3+4-4 \sqrt{3}=7-4 \sqrt{3} \\ (2- \sqrt{2})^2=4+2-4 \sqrt{2} =6-4 \sqrt{2} \\ (3- \sqrt{3})^2=9+3-6 \sqrt{3}=12-6 \sqrt{3} \\ (3 \sqrt{2}-1)^2=18+1-6 \sqrt{2}=19-6 \sqrt{2} \\ (1+ \sqrt{3})(1- \sqrt{3})=1-3=-2 [/tex]