Question

Calculeaza A:(28,2-25,8):12+9,8
B:[11,2(3)-9,(2)]-1\100
C:(4,56+16,23-2,39):8
Determina 3a+2b+c:
Determina media aritmetica a numerelor a,b,c, unde a,b,c sunt determinate de ex anterioare

Answer 1

A=(28,2-25,8):12+9,8=2,4:12+9,8=0,2+9,8=10
B=[11,2(3)-9,(2)]-1/100=[(1123-112)/90-(92-9)/9]-1/100=
=1011/90-83/9-1/100= 10110-8300-9=1801/900
C=(4,56+16,23-2,39):8 =18,56:8=2,32
Determina 3a+2b+c
3x10+2x1801/900+2,32=30+1801/450+2,32=32,32+1801/450=(14544+1801)/450= =16345/450=3269/90
(10+1801/900+2,32)/3=(9000+1801+2088)/3*900=12889/3*900=4,773(703)