Question

calculeaza repegulil e invatate (4+3)×(9-6)= b)100:10×(7+3)= c (9-9)×9+3×3×3= d 89-35:(5+2)+43=

Answer 1

a)(4+3) x (9-6) = 21 (se calculeaza mai intai paranteza)
7 x 3 = 21 
b)100:10x(7+3) =100(se calculeaza mai intai parateza)
100:10x10=100
10x10=100
c)(9-9)x9+3x3x3=       (se calculeaza mai intai paranteza)
0x9+3x3x3=
0+27=27
d)89-35:(5+2)+43=127
 89-35:7+43=127          (se face mai intai impartirea)
 89-5+43=127
 84+43=127
        

Answer 2

7×3=21
10×10=100
0×9+9×3=27
89-35:7+43=84+43=127
Sper ca teama ajutat!