Question

care sunt cele trei nr consecutive pare carora suma este 4740

Answer 1

a /__/

b /__/ + 2

c /__/ + 2 + 2

4740 suma

2 + 2 + 2 = 6

1 + 1 + 1 = 3 ( segmente egale )

4740 - 6 = 4734 ( 3 segmente egale )

4734 : 3 = 1578 ( a )

1578 + 2 = 1580 ( b )

1578 + 2 + 2 = 1582 ( c)

Answer 2

a /-------/
b /-------/+2
c /-------/+4

4740 - (2+4) = 4740 - 6 = 4 734
4 734 : 3 = 1 578

a = 1 578
b = 1 578 + 2 = 1 580
c = 1 578 + 4 = 1 582

Verificam:
1 578 + 1 580 + 1 582 = 4 740