Question

Combinari de 12 luate câte 2

Answer 1

=$\frac{12!}{2!(12-2)!}= \frac{12!}{2*10!}= \frac{10!*11*12}{2*10!}= \frac{11*12}{2}=66$

Answer 2

[tex]C_{m}^n= \frac{m!}{n!(m-n)!}\\ C_{12}^2= \frac{12!}{2!(12-2)!} = \frac{10!*11*12}{2!*10!}=11*6=66 [/tex]