Question

comparați x cu y cunoscând: x=[(2^3)^5+125^5+7^35:7^20]:(2^15+7^15+5^15)x 3^26
y=2^101 :[(5^171:5^170-3)^98+2^105:(2^3x2^4)+(2^11)^9]x2^38​

Answer 1

Răspuns:

x= [(2³)⁵+125⁵+7³⁵:7²⁰] : (2¹⁵+7¹⁵+5¹⁵)•3²⁶

x= (2¹⁵ +(5³)⁵+7¹⁵) : (2¹⁵+7¹⁵+5¹⁵)•3²⁶

x= ( 2¹⁵+5¹⁵+7¹⁵) : (2¹⁵+7¹⁵+5¹⁵) • 3²⁶

x= 1 • 3²⁶

x = 3²⁶

y= 2¹⁰¹ :[(5¹⁷¹: 5¹⁷⁰- 3)⁹⁸+2¹⁰⁵:(2³•2⁴)+(2¹¹)⁹]•2³⁸

y= 2¹⁰¹:[(5¹-3)⁹⁸+2¹⁰⁵:2⁷+2⁹⁹]•2³⁸

y= 2¹⁰¹ : (2⁹⁸+2⁹⁸+2⁹⁹)•2³⁸

y= 2¹⁰¹: 2⁹⁸•(1+1+2¹)•2³⁸

y= 2¹⁰¹ :2⁹⁸•4•2³⁸

y=2³• 4 • 2³⁸

y= 2³•2²•2³⁸

y= 2⁴³