Question

Dacă 2014(x^2-6x+9)+2015* radical din(y^2+10y+25)=0 , atunci x-y are valoarea

Answer 1

   
[tex]\displaystyle\\ 2014(x^2-6x+9)+2015\sqrt{(y^2+10y+25)}=0\\\\ 2014(x-3)^2+2015\sqrt{(y+5)^2}=0\\\\ 2014(x-3)^2+2015\cdot \Big|(y+5)\Big|=0\\\\ \Longrightarrow~~~x-3 = 0~~~si~~~y+5=0\\\\ x=\boxed{\bf 3}\\\\ y = \boxed{\bf -5}\\\\ x - y = 3 - (-5)=3+5= \boxed{\boxed{\bf 8}}[/tex]