Question

Daca avem triunghiul ABC si B are 9o grade AB are 6cm , AC `1o cm atunci BC cati cm are ?
Sunt clasa a 7

Answer 1

AC_Ipotenuza
AB, BC- catete
AC=10
AB=6

Pitagora

AC^2=AB^2+BC^2
10^2=6^2+BC^2
BC^2=100-36
BC^2=64
BC= radical din 64 
BC=8

Answer 2

Se aplica teorema lui Pitagora:
$AC^{2} = BC^{2} + BA^{2} => BC^{2} = AC^{2} - BA^{2}$$=> BC^{2} = \sqrt{100-36} =64 => BC= 8$