Question

Daca nr x,y,z , st invers proportionale cu nr 2⁻¹ , 2⁻² , 2⁻³ si x-2y+z=12 , atunci x=... z=,,,,, y=....
VA ROGGG ! E URGENT

Answer 1

x/1/2la-1=y/1/2la-2=z/1/2la-3
x/2=y/2²=z/2³
x/2=y/4=z/8
x=2z/8=z/4
y=4z/8=z/2
x-2y+z=12
z/4-2z/2+z=12
z/4-z+z=12
z/4=12⇒z=4·12=48
x=z/4=48/4=12
y=z/2=48/2=24