Question

Daca radical din 32-radical din 98-radical din 8= xradical din 2

Answer 1

$\sqrt{32} - \sqrt{98}-\sqrt8 = x\sqrt2 \\ \\ \sqrt{2\cdot 16}-\sqrt{2\cdot 49}-\sqrt{2\cdot 4} = x\sqrt2 \\ \\ \sqrt{16}\cdot \sqrt2-\sqrt{49}\cdot\sqrt2-\sqrt4\cdot \sqrt2=x\sqrt2 \\ \\ 4\sqrt2-7\sqrt2-2\sqrt2 = x\sqrt2 \\ \\ (4-7-2)\cdot \sqrt2 = x\sqrt2 \\ \\ -5\sqrt2 = x\sqrt2 \\ \\ \Rightarrow \boxed{x = -5}$