Question

Daca x(4x+23)=6, x=?

Answer 1

[tex] x(4x+23)=6 \\ 4x²+23x-6=0 \\ ∆=529-4*4*(-6) \\ ∆=625 [tex] $x_{1} = \frac{-23- \sqrt{625} }{2*4} = \frac{-23-25}{8} = -6 \\ x_{2} = \frac{-23- \sqrt{625} }{2*4} = \frac{-23+25}{8} = \frac{1}{4}$