Question

Dau coroana va rog ajutați-mă ​

Answer 1

Explicație pas cu pas:

a)

$x - x + x = x$

b)

$= (2 {a}^{3} + {a}^{3} - 4 {a}^{3}) - a = - {a}^{3} - a$

c)

$= (- {x}^{3} + 0.5{x}^{3}) + \Big( \dfrac{1}{2}{x}^{2} - {x}^{2} \Big) + (2x - 2.5x) + \sqrt{5} = - 0.5 {x}^{3} - 0.5 {x}^{2} - 0.5x + \sqrt{5}$

d)

$= (2xy - 3xy) + \Big( \dfrac{4x}{3} - 2x - \dfrac{(56 - 5)}{9}x \Big) = - xy + \Big( \dfrac{4x}{3} - 2x - \dfrac{51x}{9} \Big) = - xy + \dfrac{4 - 6 - 17}{3} x = - xy - \dfrac{19x}{3}$

e)

$= \Big( \dfrac{11}{6} {x}^{2} - 9 {x}^{2} - 1.8(3) {x}^{2} \Big) + (5a - a) + ( - 2xy + 7xy) + (- 0.5x {y}^{2} - \dfrac{3}{2} x {y}^{2}) = \Big( \dfrac{11}{6} {x}^{2} - 9 {x}^{2} - \dfrac{183 - 18}{90} {x}^{2} \Big) + 4a + 5xy + ( - 0.5x {y}^{2} - 1.5 x {y}^{2}) = \Big( \dfrac{11}{6} {x}^{2} - 9 {x}^{2} - \dfrac{11}{6} {x}^{2} \Big) + 4a + 5xy - 2x {y}^{2} = - 9 {x}^{2} + 4a + 5xy - 2x {y}^{2}$