Question

David a avut o suma de bani,pa care a cheltuit-o astfel;1/2 din total si-a cumparat o pereche de adidasi,2/5 din total si-a cumparat un treining iar 1/16 din total si-a cumparat o minge.Cati lei a avut David,daca i-au mai ramas 15 lei..va rog mult!

Answer 1

y/2⇒adidasi;
2y/5⇒treining;
y/16⇒minge;
⇒y-y/2=2y/2-y/2=y/2;
⇒y/2-2y/5=5y/10-4y/10=y/10;
⇒y/10-y/16=8y/80-5/80=3y/80;
⇒3y/80=15
⇒y=80·15/3
⇒y=80·5
⇒y=400[lei-a avut David];

Answer 2

pret adidasi = 1/2×T=T/2
pret trening=2/5×T=2T/5
pret minge=1/16×T=T/16
total= ret adidasi+pret minge+pret trening
total T= T/2+2T/5+T/16 +15  aducem la acelasi numitor, APOI IL ELIMINAM
T×2×5×16=T×5×16+2T×2×16+15×2×5×16
 160T=80T+64T+2400
160T-80T-64T=2400
16T=2400
T=2400/16
=150