Question

determinati cantiteatea de substanta si masa piritei care se va consuma la producerea oxidului de sulf cu masa de 128 kg

Answer 1

m=M*V
rezolvare:
M(SO2)=32*1+16*2=64 g/mol
m(SO2)=64g/mol*8mol=512g
x mol/4 mol=128000g/512g;
x mol=128000g*4 mol/512g=1000mol
M(FeS2)=56*1+32*2=120000g/mol
m(FeS2)=1000mol*120g/mol=120000g
raspuns:
V(FeS2)=1000mol
m(FeS2)=120000g=120kg