Question

Determinati masurile a doua unghiuri adiacente suplimentare , daca aceste masuri sunt egale numeric in grade cu valorile expresiilor x²-6x + 80grade si 4x+20grade , unde x∈ N.

Answer 1

a=x²-6x+80grade
b=4x+20grade
a+b=180 grade
(x²-6x+80grade)+(4x+20grade)=180 grade
x²-2x+100-180=0
x²-2x-80=0
(x-8)(x-10)=0
x-8=0
x1=8
x-10=0
x=10
daca x=8⇒a=8²-6·8+80=64-48+80=96
                 b=4·8+20=32+20=52
a+b=96+52=148 deci x=8 nu e bun

daca x=10⇒a=10²-6·10+80=100-60+80=120
                  b=4·10+20=60
a+b=120+60=180
deci ung.a=120 grade si ung.b=60 grade