Question

Determinati numerele intregi x si y pentru care
(2x+1)y=21
(x-4)(y+3)=35

Answer 1

(2x+1)y=21⇔(2x+1)*y=3*7
y=3
2x+1=7⇒2x=6⇒x=3
(x-4)(y+3)=35
(x-4)(y+3)=7*5
x-4=7         x-4=5
x=11          x=9
y+3=5         y+3=7
y=2              y=4