Question

Determinati perechile de numere reale (a,b) pentru care are loc egalitatea : 
$\frac{a-1}{2}$ = $\frac{3}{b+1}$ . 

Answer 1

$\dfrac{a-1}{2}=\dfrac{3}{b+1}\Rightarrow a=\dfrac{6}{b+1}+1=\dfrac{b+7}{b+1}$

luam $b=m\in\mathbb R$ si avem:

$(a;b)\in\left\{\left(\dfrac{m+7}{m+1};\ m\right)|m\in\mathbb R\right\}$