Question

Dupa ce a depasit cu2/7km jumatatea traseului unei excursii,autocarul ce ducea elevii in excursie mai avea de parcurs 37km pana la destinatie.Ce distanta dus-intors a parcurs autocarul?.

Answer 1

y/2+27km=37km
⇒y/2=37km-27km
⇒y/2=10km
⇒y=2·10km⇒20km[dus]⇒intors=dus⇒20km;
⇒20km·2=40km[dus-intors-a parcurs autocarul];

Answer 2

o sa consider  depasirea 27 km
x=traseul
x/2+27+37=x
x/2+64=x
x+128=2x
x=128 km
128x2=256 km dus intors