Question

e si m rezolvare completa repede

Answer 1

e) o rescriem si obținem:

$z^{2} -6z+34=0$

a=1

b=-6

c=34

Δ=$b^{2}-4ac$

Δ=$(-6)^{2} -4*1*34$

Δ=36-136

Δ=-100

z1=$\frac{6+\sqrt{-100} }{2}$

z2=$\frac{6-\sqrt{-100} }{2}$

=>z∉R

m)$p^{2} -26p+165=0$

$p^{2} -11p-15p+165=0$

$p(p-11)-15(p-11)=0$

$(p-11)(p-15)=0$

p1=>p-11=0=>p1=11

p2=>p-15=0=>p2=15