Question

Efectuați:

(3/5)^7:(2-1 intreg 2/5)^4+5:1 întreg 1/4-(3/5)^3

(2-4/3)^2-2/9+(1/3)^2

(1 întreg 1/2-2/3)^3:(5/6)^2+(1 întreg 2/3-4/5)^2:(2 întregi 3/5)^2

[4/3-0, (3)]^2:0,25

Rog urgent! !!!! Mulțumesc Cine mă poate ajuta dau coroana !!! Plz! !!!!!!! Ajutor! !!!

Answer 1

(3/5)^7:(2-1 intreg 2/5)^4+5:1 întreg 1/4-(3/5)^3=
=(3/5)^7:(2-7/5)^4+5:5/4-(3/5)^3=
=(3/5)^7:(-3/5)^4+4-(3/5)^3=
=(3/5)^3+4-(3/5)^3=4

(2-4/3)^2-2/9+(1/3)^2=
=(2/3)^2-2/9+(1/3)^2=
=4/9-2/9+1/9=
=3/9=1/3

 (1 întreg 1/2-2/3)^3:(5/6)^2+(1 întreg 2/3-4/5)^2:(2 întregi 3/5)^2=
= (3/2-2/3)^3:(5/6)^2+(5/3-4/5)^2:(13/5)^2=
= (9/6-4/6)^3:(5/6)^2+(25/15-12/15)^2:(13/5)^2=
= (5/6)^3:(5/6)^2+(13/15)^2 *(5/13)^2=
=5/6+1/3^2=5/6+1/9=(15+2)/18=17/18

[4/3-0, (3)]^2:0,25 =
=[4/3-3/9]^2:25/100 =
=[4/3-1/3]^2:1/4 =
=1^2:1/4 =
=1*4=4