Question

ex 2,3 chimie ,dau punctaj maxim​

Answer 1

2.

miu H2 = 2 g/mol

54/2 = 27 moli

miu NH3 = 17 g/mol

34/17 = 2 moli

4,48/22,4 = 0,2 moli CO

2,24/22,4 = 0,1 moli SO3

3.

67,2/22,4 = 3 moli HCl

miu.HCl = 36,5 g/mol

=> m = 36,5x3 = 109,5 g HCl

miu.H2S = 2+32 = 34 g/mol

2x34 = 68 g H2S