Question

Ex 3 va rog dau 30 pct

Answer 1

$A \ semicerc = \frac{1}{2} *A\ cerc. \\ \\ A \ semicerc = \frac{1}{2} * 2 \pi R = \frac{2 \pi* 3} {2} = \frac{3 \pi}{1} \\ \\ \pi = 3,14 =\ \textgreater \ \ A \ semicerc \ = 3*3,14 = 9,42 (m^{2} )$

Answer 2

A cercului = 2pi r
A semicerc. = A cerc/2 = > 2pir/2 = > pi r  = > 3,14 x 3 = 9,42 m^2