Question

Exercitiul 3, va rog!

Answer 1

Salut.

$xeR\\arcsin(x)+arcsin(\frac{1}{2} )=\frac{\pi }{3}\\arcsin(x)+\frac{\pi }{6}=\frac{\pi }{3} \\arcsin(x)=\frac{\pi }{3}-\frac{\pi }{6}=\frac{2\pi-\pi  }{6}=\frac{\pi }{6} \\x=sin(\frac{\pi }{6})=\frac{1}{2}$