Question

Expresia va rog!!!!!

Answer 1

Rezolvarea o gasiti in atas

Answer 2

$\it E(x) = \left(\dfrac{(x+2)^2}{x^2+4}-1 \right):\dfrac{x}{x^2+4}= \left(\dfrac{x^2+4x+4}{x^2+4}-1 \right)\cdot\dfrac{x^2+4}{x}=$

$=\it \dfrac{x^2+4x+4}{x^2+4}\cdot \dfrac{x^2+4}{x} -\dfrac{x^2+4}{x} =\dfrac{x^2+4x+4}{x} - \dfrac{x^2+4}{x} =$

$\it \dfrac{x^2+4x+4 -x^2-4}{x} = \dfrac{4x}{x} = 4$