Question

Găsiți punctul A(x,0) situat la distanta 10 fata de B(4,6)​

Answer 1

$10=\sqrt{\left(4-x\right)^2+\left(6-0\right)^2}\\10=\sqrt{16-8x+x^2+36}\\100=x^2-8x+52\\x^2-8x-48=0\\\Delta =64-4\left(-48\right)=64+192=256\\x_{1,2}=\frac{8\pm 16}{2}\\x_1=12,\:x_2=-4$