Question

Împartind suma a trei numere naturale consecutive la 7 , obtinem catul 13 si restul 5 . Aflati cele trei numere .

Answer 1

(a + a + 1 + a + 2) : 7 = 13 rest 5
a + a + 1 + a + 2 = 7 * 13 + 5
3a + 3 = 96
3a = 96 - 3
a = 93 : 3
a = 31
a + 1 = 31 + 1 = 32
a + 2 = 31 + 2 = 33
 

Answer 2

$\frac{a+b+c}{7}=13$ rest 5
$a+b+c=13*7+5 \\ a+b+c=91+5 \\ a+b+c=96 \\ a=a \\ b=a+1 \\ c=b+1=a+2 \\ a+a+1+a+2=96 \\ 3a+3=96 \\ 3a=96-3 \\ 3a=93 \\ a=\frac{93}{3} \\ a=31 \\ b=a+1=31+1=32 \\ c=b+1=32+1=33$