Question

impartind suma a trei numere naturale consecutive la 7, obtinem catul 13 si restul 5. Aflati cele trei numere

Answer 1

(a+a+1+a+2):7=13 rest 5

3a+3=91+5

3a=96-3

3a=93

a=31

a+1=31+1=32
a+2=31+2=33

Answer 2

(x+x+1+x+2):7=13 rest 5
3x+3=13*7+5
3x+3=96
3x=93
x=31

x+1=31+1=32
x+2=31+2=33