Question

impartiti nr 4625 in parti invers proportionate cu 8,12 si 10

Answer 1

 { a,b ,c } - {8,12,10}
a · 8=b·12=c·10=k
8a=k⇒ a=k/8
12b=k⇒ b= k/12
10c=k⇒ c= k/10
a +b +c= 4625
k/8+k/12+k/10=4625
 ( k/8 se amplifica cu 15 , k/12 se amplifica cu 10 , k/ 10 se amplifica cu 12 )
15k+10 k+ 12k (totul  supra 120 )=4625
37k (totul supra 120 )= 4625
37k= 4625 ·120
37k= 555000
k= 555000: 37
k=15000
a= 15000:8 =1875
b=15000:12=1250
c=15000:10=1500