Question

Impartiti numarul 120 in parti invers proportionale respectiv cu numerele 0,2; 0,5; 0,25.

Answer 1

a+b+c=120
a=k/0.2=5k
b=k/0.5=2k
c=k/0.25=4k

5k+2k+4k=120
11k=120
k=10.9

a=5*10.9
a=54.5

b=2*10.9
b=21.8

c=4*10.9
c=43.6