Question

In ce masa de sare gema de puritate 80 % se afla 7,1 g Cl

Answer 1

Sare gema  = NaCl

M NaCl = 58,5 uam

58,5 g NaCl _______ 35,5 g Cl

x g NaCl ___________ 7,1 g Cl

x= 11,7 g NaCl

puritate 80% ⇒

100g substanta impura ( sare gema) _____ 80 g NaCl pur

x g substanta impura __________________ 11,7 g NaCl pur

x=14,625 g sare gema