Question

in prima cutie sint 18 intreg si 2/3kg de mere , ceea ce constituie cu 3intreg si 5/6 kg mai mult decit in cutia a doua. Cite kg de mere sint in cutia a treia, daca, in total, in cele 3 cutii sint 50 intreg si 1/9 kg de mere?

Answer 1

Schema:
I cutie- $18\frac{2}{3}$ kg de mere
II cutie- ? kg de mere, cu $3\frac{5}{6}$ mai putin decit in prima
III cutie- ? kg de mere
In total avem $50 \frac{1}{9}$ kg
Rezolvare:
1) $18 \frac{2}{3}- 3\frac{5}{6}= 14\frac{5}{6}$ kg  sunt in a 2a cutie
2)$18 \frac{2}{3}+14 \frac{5}{6}= 33\frac{1}{2}$ kg sunt in 1a si a 2a cutie
3)$50\frac{1}{9}-33 \frac{1}{2}= 16\frac{11}{18}$ kg sunt in a 3a cutie
Raspuns: In a 3a cutie sunt $16 \frac{11}{18}$ kg de mere.
Sper ca te-am ajutat....