Question

Integrala de la 1 la e din f(x) supra x dx. f(x) = 2$x^{2}$ - 2x

Answer 1

$\int\limits^e_1 { \frac{2x^2-2x}{x} } \, dx = \int\limits^e_1 {(2x-2)} \, dx = (x^{2} -2x)=e^2-2e-1+2= \\ =e^2-2e+1=(e-1)^2$