Question

Intr-un recipient cu volumul de 6l se afla 16,8g de hidrocarbura la temperatura de 27 C si presiunea de 1,23atm. Hidrocarbura contine 14,28% Hidrogen si 85,72% Carbon. Determinati formula moleculara a hidrocarburii.

Answer 1

-AFLU masa molara din ecuatia de stare:
pV= nRT,   pV= mRT/M  --->1,23x6=16,8x0,082x(273+27)/M-->M=56g/mol
-aflu formula moleculara a hidrocarburii CxHy
100g hidrocarbura.....14,28g/1g/molH......85,72g/12g/mol
56g...............................n.,molH............................n',molC
n=8 moLH
n' =4molC-----------. > C4H8....PROPENA