Question

log² 225=
log³ 9 + log ³ 1=
log³ 9 - log³ 1=
log⁴⁹ 343=
log¹²⁵ 1024=​

Answer 1

Răspuns:

Explicație pas cu pas:

Baza se scrie jos, nu sus

log2(225) = log2(15^2) = 2*log2(15)

log3(3^2) +log3(1) = 2 +0 = 2

log3(3^2) -log3(1) = 2 -0 = 2

log49(7^3) = log7(7^3)/log7(49) =

  log7(7^3)/log7(7^2) = 3/2  

log125(1024)  ?? e ceva gresit