Question

m=? a.i valoarea minima a functiei sa fie 5

 functia-  x patrat+mx+2=0

Answer 1

Valoarea minima= $y _{min} =5$
$y_{min} = \frac{- \alpha }{4a}$  ( $\alpha$ = delta- Δ)
Δ=$b^{2} -4ac$
Δ=$m^{2} - 8$
$=>\frac{-m ^{2}+8 }{4} =5 => - x^{2} +8 =20$
$=> -m^{2} =12 => m= \sqrt{12}=2 \sqrt{3}$
Eu am luat cazul in care x nu are minus in fata.