Question

ma poate ajuta cineva?

Answer 1

$\frac{1 + \sqrt{2} }{ \sqrt{3} + \sqrt{6} } = \frac{(1 + \sqrt{2} )( \sqrt{6} - \sqrt{3}) }{6 - 3} = \frac{ \sqrt{6} - \sqrt{3} + 2 \sqrt{3} - \sqrt{6} }{3} = \frac{ \sqrt{3} }{3} \\ deci \: a = b = 3$