Question

Mă poate ajuta cineva la 3 şi 4?​

Answer 1

Răspuns:

Explicație pas cu pas:

3)

a)

=(5/3)⁸⁺⁴

=(5/3)¹²

-

b)

=(7/11) ¹⁵⁻⁷

=(7/11)⁸

-

-

c)

=(11/13)⁴ˣ³

= (11/13)¹²

-

d)

=( 5/12)⁶⁴

-

-

4)

a)

= (5/8)⁶⁺⁷ :(5/8)⁸

= (5/8)¹³:( 5/8)⁸

= (5/8)¹³⁻⁸

= (5/8)⁵

-

-

b)

= (8/7)³ˣ⁴:( 8/7)¹⁰

= (8/7)¹²:( 8/7)¹⁰

= (8/7)¹²⁻¹⁰

= (8/7)²

-

c)

=[(11/9 )⁶⁺⁵]³: ( 11/9)²²

= [(11/9)¹¹]³: (11/9)²²

=[ (11/9)¹¹ˣ³]:(11/9)²²

= (11/9)³³: (11/9)²²

= (11/9)³³⁻²²

= (11/9)¹¹

-

-

d)

=[( 1/5)²⁰ˣ⁵ ]- (1/5)¹⁰⁰

= (1/5)¹⁰⁰- (1/5)¹⁰⁰

= 0