Ma poate ajuta cineva va rog
Răspunsuri la întrebare
Răspuns:
1.
a)
BC^2=AB^2+AC^2
BC^2=25+75
BC^2=100
BC=10
sinB=AC/BC
sinB=5/10 = 1/2
sin30 = 1/2, <B = 30
<C = 60
b)
DF^2=EF^2-DE^2
DF^2=72-36
DF^2=36
DF=6
DF=EF | => <E = <F = (180-90)/2 = 90/2 = 45
c)
LK^2=LM^2-KM^2
LK^2=12-3
LK^2=9
LK=3
sinL =√3/2√3 = 1/2
sin30 = 1/2, <L = 30
<M = 60
d)
<C=60
BC = 2√7
AB^2=BC^2-AC^2
AB^2=(2√7)^2-√7^2
AB^2=28-7
AB^2=21
AB=√21
e)
<F = 45
DE=DF=3
EF^2=2DE^2
EF^2=2(3^2)
EF^2=2*9
EF^2=18
EF=3√2
f)
<L = 30
sinM = 4/LM
sin60 = 4/LM
√3/2 = 4/LM
LM=4√3
KM=2√3
2)
a)
DR^2=SR^2-SD^2
DR^2=(6√2)^2-6^2
DR^2=72-36
DR^2=36
DR=6
<DSR=<DRS=45
RQ=6+2√3
SQ^2=SD^2+QD^2
SQ^2=6^2+(2√3)^2
SQ^2=36+12
SQ^2=48
SQ=4√2
b)
Fie TX perpendicular UY, X {> UY
TUY triunghi isoscel | => TX -> mediana, bisectoare
TX mediana | => UX = 4√3
TX^2=TU^2-UX^2
TX^2=8^2-(4√3)^2
TX^2=64-48
TX^2=16
TX=4
sinU = TX/TU
sinU = 4/8
sinU = 1/2
sin30 = 1/2, <U = 30
<U=<Y=30
<T=180-60
<T=120
Răspuns:
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