Question

matematica ajutorrr urgent

Answer 1

Ai rezolvarea pe foaie.

Answer 2

$\displaystyle E(x)=\left( \frac{5}{x-2} + \frac{2}{x+2} - \frac{6}{x^2-4} \right):\left( \frac{x^2+4}{x^2-4}+1 \right)\\ \\ E(x)= \left( \frac{5}{x-2} + \frac{2}{x+2} - \frac{6}{(x-2)(x+2)} \right):\left( \frac{x^2+4}{(x-2)(x+2)} +1\right) \\ \\ E(x)= \frac{5(x+2)+2(x-2)-6}{(x-2)(x+2)} : \frac{x^2+4+(x-2)(x+2)}{(x-2)(x+2)} \\ \\ E(x)= \frac{5x+10+2x-4-6}{(x-2)(x+2)} \cdot \frac{(x-2)(x+2)}{x^2+4+x^2-4} \\ \\ E(x)= \frac{7x}{2x^2} \\ \\ E(x)= \frac{7}{2x}$