Question

modul din x=5-3 radical din 3
pls​

Answer 1

$\it \sqrt3>1,73|_{\cdot3} \Rightarrow 3\sqrt3>5,19|_{\cdot(-1)} \Rightarrow -3\sqrt3<-5,19|_{+5} \Rightarrow \\ \\ \Rightarrow 5-3\sqrt3<-0,19<0\\ \\ \\ |x|=\underbrace{5-3\sqrt3}_{<0} \Rightarrow S=\varnothing$